From 4e18a599b0d737086ecaed10f73751862324b30a Mon Sep 17 00:00:00 2001
From: jim winstead <jimw@php.net>
Date: Wed, 31 Oct 2001 02:02:20 +0000
Subject: [PATCH] put overflow examples together, and division example on its
 own. fix typo and another dash.

git-svn-id: https://svn.php.net/repository/phpdoc/en/trunk@61232 c90b9560-bf6c-de11-be94-00142212c4b1
---
 language/types.xml | 46 +++++++++++++++++++++++-----------------------
 1 file changed, 23 insertions(+), 23 deletions(-)

diff --git a/language/types.xml b/language/types.xml
index 007557d18f..17d8f3c92e 100644
--- a/language/types.xml
+++ b/language/types.xml
@@ -1,5 +1,5 @@
 <?xml encoding="iso-8859-1"?>
-<!-- $Revision: 1.57 $ -->
+<!-- $Revision: 1.58 $ -->
  <chapter id="language.types">
   <title>Types</title>
 
@@ -312,38 +312,26 @@ $a = 0x1A; # hexadecimal number (equivalent to 26 decimal)
     <sect2 id="language.types.integer.overflow">
      <title>Integer overflow</title>
      <para>
-      If you specify a number beyond the bounds of the <type>integer</type> type,
-      it will be interpreted as a <type>float</type> instead.
-     </para>
-     <para>
-      In PHP there is also no such thing as integer division.
-      <literal>1/2</literal> yields the <type>float</type>
-      <literal>0.5</literal>. <!-- See ??? for more information. (with the
-      operators, or with type-jug) -->
+      If you specify a number beyond the bounds of the <type>integer</type>
+      type, it will be interpreted as a <type>float</type> instead. Also, if
+      you perform an operation that results in a number beyond the bounds of
+      the <type>integer</type> type, a <type>float</type> will be returned
+      instead.
+
       <informalexample>
        <programlisting role="php">
 $large_number =  2147483647;
 var_dump($large_number);
 // output: int(2147483647)
+
 $large_number =  2147483648;
 var_dump($large_number);
 // output: float(2147483648)
 
 // this goes also for hexadecimal specified integers:
-
 var_dump( 0x80000000 );
 // output: float(2147483648)
 
-var_dump( 25/7 );
-// output: float(3.5714285714286)
-       </programlisting>
-      </informalexample>
-      Furthermore, if some function or operator yields a number that is beyond
-      the boundaries of <type>integer</type>, it will also 
-      be automatically converted to 
-      <type>float</type>.
-      <informalexample>
-       <programlisting role="php">
 $million = 1000000;
 $large_number =  50000 * $million;
 var_dump($large_number);
@@ -360,10 +348,22 @@ var_dump($large_number);
         positive there is no problem.
        </simpara>
        <simpara>
-        This is solved in PHP 4.1.0
+        This is solved in PHP 4.1.0.
        </simpara>
       </warning>
      </para>
+     <para>
+      There is no integer division operator in PHP.
+      <literal>1/2</literal> yields the <type>float</type>
+      <literal>0.5</literal>. <!-- See ??? for more information. (with the
+      operators, or with type-jug) -->
+      <informalexample>
+       <programlisting role="php">
+var_dump( 25/7 );
+// output: float(3.5714285714286)
+       </programlisting>
+      </informalexample>
+     </para>
     </sect2>
    
 
@@ -373,8 +373,8 @@ var_dump($large_number);
        To explicitly convert a value to <type>integer</type>, use either
        the <literal>(int)</literal> or the <literal>(integer)</literal> cast.
        However, in most cases you do not need to use the cast, since a value
-       will be autmatically converted if an operator, function or 
-       control structure requires a <type>integer</type>-argument.
+       will be automatically converted if an operator, function or 
+       control structure requires a <type>integer</type> argument.
       </simpara>
       <simpara>
        See also <link linkend="language.types.type-juggling">type-juggling</link>.