php-doc-en/language/references.xml

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<?xml version="1.0" encoding="iso-8859-1"?>
<!-- $Revision: 1.46 $ -->
<chapter id="language.references">
<title>References Explained</title>
<sect1 id="language.references.whatare">
<title>What References Are</title>
<simpara>
References in PHP are a means to access the same variable content
by different names. They are not like C pointers; instead, they are
symbol table aliases. Note that in PHP, variable name and variable
content are different, so the same content can have different names.
The most close analogy is with Unix filenames and files -
variable names are directory entries, while variable contents is
the file itself. References can be thought of as hardlinking in
Unix filesystem.
</simpara>
</sect1>
<sect1 id="language.references.whatdo">
<title>What References Do</title>
<para>
PHP references allow you to make two variables to refer to the
same content. Meaning, when you do:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
$a =& $b;
?>
]]>
</programlisting>
</informalexample>
it means that <varname>$a</varname> and <varname>$b</varname>
point to the same content.
<note>
<para>
<varname>$a</varname> and <varname>$b</varname> are completely
equal here, that's not <varname>$a</varname> is pointing to
<varname>$b</varname> or vice versa, that's
<varname>$a</varname> and <varname>$b</varname> pointing to the
same place.
</para>
</note>
</para>
<note>
<para>
If array with references is copied, its values are not dereferenced.
This is valid also for arrays passed by value to functions.
</para>
</note>
<para>
The same syntax can be used with functions, that return references,
and with <literal>new</literal> operator (in PHP 4.0.4 and later):
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
$bar =& new fooclass();
$foo =& find_var($bar);
?>
]]>
</programlisting>
</informalexample>
Since PHP 5, <link linkend="language.oop5.basic.new">new</link> return
reference automatically so using <literal>=&amp;</literal> in this
context is deprecated and produces E_STRICT level message.
</para>
<note>
<para>
Not using the <literal>&amp;</literal> operator causes a copy of the
object to be made. If you use <literal>$this</literal> in the class it
will operate on the current instance of the class. The assignment without
<literal>&amp;</literal> will copy the instance (i.e. the object) and
<literal>$this</literal> will operate on the copy, which is not always
what is desired. Usually you want to have a single instance to work with,
due to performance and memory consumption issues.
</para>
<para>
While you can use the <literal>@</literal> operator to
<emphasis>mute</emphasis> any errors in the constructor when using it as
<literal>@new</literal>, this does not work when using the
<literal>&amp;new</literal> statement. This is a limitation of the Zend
Engine and will therefore result in a parser error.
</para>
</note>
<warning>
<para>
If you assign a reference to a variable declared <literal>global</literal>
inside a function, the reference will be visible only inside the function.
You can avoid this by using the <varname>$GLOBALS</varname> array.
<example>
<title>Referencing global variables inside function</title>
<programlisting role="php">
<![CDATA[
<?php
$var1 = "Example variable";
$var2 = "";
function global_references($use_globals)
{
global $var1, $var2;
if (!$use_globals) {
$var2 =& $var1; // visible only inside the function
} else {
$GLOBALS["var2"] =& $var1; // visible also in global context
}
}
global_references(false);
echo "var2 is set to '$var2'\n"; // var2 is set to ''
global_references(true);
echo "var2 is set to '$var2'\n"; // var2 is set to 'Example variable'
?>
]]>
</programlisting>
</example>
Think about <literal>global $var;</literal> as a shortcut to <literal>$var
=&amp; $GLOBALS['var'];</literal>. Thus assigning other reference
to <literal>$var</literal> only changes the local variable's reference.
</para>
</warning>
<note>
<para>
If you assign a value to a variable with references in a <link
linkend="control-structures.foreach">foreach</link> statement,
the references are modified too.
<example>
<title>References and foreach statement</title>
<programlisting role="php">
<![CDATA[
<?php
$ref = 0;
$row =& $ref;
foreach (array(1, 2, 3) as $row) {
// do something
}
echo $ref; // 3 - last element of the iterated array
?>
]]>
</programlisting>
</example>
</para>
</note>
<warning>
<para>
Complex arrays are sometimes rather copied than referenced. Thus following
example will not work as expected.
<example>
<title>References with complex arrays</title>
<programlisting role="php">
<![CDATA[
<?php
$top = array(
'A' => array(),
'B' => array(
'B_b' => array(),
),
);
$top['A']['parent'] = &$top;
$top['B']['parent'] = &$top;
$top['B']['B_b']['data'] = 'test';
print_r($top['A']['parent']['B']['B_b']); // array()
?>
]]>
</programlisting>
</example>
</para>
</warning>
<para>
The second thing references do is to pass variables
by-reference. This is done by making a local variable in a function and
a variable in the calling scope reference to the same content. Example:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
function foo(&$var)
{
$var++;
}
$a=5;
foo($a);
?>
]]>
</programlisting>
</informalexample>
will make <varname>$a</varname> to be 6. This happens because in
the function <varname>foo</varname> the variable
<varname>$var</varname> refers to the same content as
<varname>$a</varname>. See also more detailed explanations about <link
linkend="language.references.pass">passing by reference</link>.
</para>
<simpara>
The third thing reference can do is <link
linkend="language.references.return">return by reference</link>.
</simpara>
</sect1>
<sect1 id="language.references.arent">
<title>What References Are Not</title>
<para>
As said before, references aren't pointers. That means, the
following construct won't do what you expect:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
function foo(&$var)
{
$var =& $GLOBALS["baz"];
}
foo($bar);
?>
]]>
</programlisting>
</informalexample>
</para>
<simpara>
What happens is that <varname>$var</varname> in
<varname>foo</varname> will be bound with
<varname>$bar</varname> in caller, but then it will be
re-bound with <varname>$GLOBALS["baz"]</varname>. There's no way
to bind <varname>$bar</varname> in the calling scope to something else
using the reference mechanism, since <varname>$bar</varname> is not
available in the function <varname>foo</varname> (it is represented by
<varname>$var</varname>, but <varname>$var</varname> has only
variable contents and not name-to-value binding in the calling
symbol table).
You can use <link linkend="language.references.return">returning
references</link> to reference variables selected by the function.
</simpara>
</sect1>
<sect1 id="language.references.pass">
<title>Passing by Reference</title>
<para>
You can pass variable to function by reference, so that function could modify
its arguments. The syntax is as follows:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
function foo(&$var)
{
$var++;
}
$a=5;
foo($a);
// $a is 6 here
?>
]]>
</programlisting>
</informalexample>
Note that there's no reference sign on function call - only on
function definition. Function definition alone is enough to
correctly pass the argument by reference. In recent versions of PHP
you will get a warning saying that "Call-time pass-by-reference" is
deprecated when you use a &amp; in <literal>foo(&amp;$a);</literal>.
</para>
<para>
The following things can be passed by reference:
<itemizedlist>
<listitem>
<simpara>
Variable, i.e. <literal>foo($a)</literal>
</simpara>
</listitem>
<listitem>
<simpara>
New statement, i.e. <literal>foo(new foobar())</literal>
</simpara>
</listitem>
<listitem>
<para>
Reference, returned from a function, i.e.:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
function &bar()
{
$a = 5;
return $a;
}
foo(bar());
?>
]]>
</programlisting>
</informalexample>
See also explanations about <link
linkend="language.references.return">returning by reference</link>.
</para>
</listitem>
</itemizedlist>
</para>
<para>
Any other expression should not be passed by reference, as the
result is undefined. For example, the following examples of passing
by reference are invalid:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
function bar() // Note the missing &
{
$a = 5;
return $a;
}
foo(bar()); // Produces fatal error since PHP 5.0.5
foo($a = 5); // Expression, not variable
foo(5); // Produces fatal error
?>
]]>
</programlisting>
</informalexample>
These requirements are for PHP 4.0.4 and later.
</para>
</sect1>
<sect1 id="language.references.return">
<title>Returning References</title>
<para>
Returning by-reference is useful when you want to use a function
to find which variable a reference should be bound to. Do
<emphasis>not</emphasis> use return-by-reference to increase performance, the
engine is smart enough to optimize this on its own. Only return references
when you have a valid technical reason to do it! To
return references, use this syntax:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
function &find_var($param)
{
/* ...code... */
return $found_var;
}
$foo =& find_var($bar);
$foo->x = 2;
?>
]]>
</programlisting>
</informalexample>
In this example, the property of the object returned by the
<varname>find_var</varname> function would be set, not the
copy, as it would be without using reference syntax.
</para>
<note>
<simpara>
Unlike parameter passing, here you have to use
<literal>&amp;</literal> in both places - to indicate that you
return by-reference, not a copy as usual, and to indicate that
reference binding, rather than usual assignment, should be done
for <varname>$foo</varname>.
</simpara>
</note>
<note>
<simpara>
If you try to return a reference from a function with the syntax:
<literal>return ($found_var);</literal> this will <emphasis>not</emphasis>
work as you are attempting to return the result of an
<emphasis>expression</emphasis>, and not a variable, by reference. You can
only return variables by reference from a function - nothing else.
<constant>E_NOTICE</constant> error is issued since PHP 4.4.0 and PHP
5.1.0 if the code tries to return a dynamic expression or a result of the
<literal>new</literal> operator.
</simpara>
</note>
</sect1>
<sect1 id="language.references.unset">
<title>Unsetting References</title>
<para>
When you unset the reference, you just break the binding between
variable name and variable content. This does not mean that
variable content will be destroyed. For example:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
$a = 1;
$b =& $a;
unset($a);
?>
]]>
</programlisting>
</informalexample>
won't unset <varname>$b</varname>, just <varname>$a</varname>.
</para>
<simpara>
Again, it might be useful to think about this as analogous to Unix
<command>unlink</command> call.
</simpara>
</sect1>
<sect1 id="language.references.spot">
<title>Spotting References</title>
<simpara>
Many syntax constructs in PHP are implemented via referencing
mechanisms, so everything told above about reference binding also
apply to these constructs. Some constructs, like passing and
returning by-reference, are mentioned above. Other constructs that
use references are:
</simpara>
<sect2 id="references.global">
<title><literal>global</literal> References</title>
<para>
When you declare variable as <command>global $var</command> you
are in fact creating reference to a global variable. That means,
this is the same as:
<informalexample>
<programlisting role="php">
<![CDATA[
<?php
$var =& $GLOBALS["var"];
?>
]]>
</programlisting>
</informalexample>
</para>
<simpara>
That means, for example, that unsetting <varname>$var</varname>
won't unset global variable.
</simpara>
</sect2>
<sect2 id="references.this">
<title><literal>$this</literal></title>
<simpara>
In an object method, <varname>$this</varname> is always a reference
to the caller object.
</simpara>
</sect2>
</sect1>
</chapter>
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